Solve each system of equations by using either substitution or elimination. r + 4s = - 8 3r + 2s = 6

Question

Mathematics

Bradley Jarvis

1 January, 09:09

Solve each system of equations by using either substitution or elimination. r + 4s = - 8 3r + 2s = 6

+5

Answers (1)

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Shyla Carter · Answer 1

We will use elimination

r+4s=-8

3r+2s=6 * 2

R+4s=-8

- (6r+4s=12)

-5r=-20

R=4. Then plug that in so 4+4s=-8 subtract the 4 and 4s=-12 s=-3

R=4

S=-3