How much pure acid should be mixed with 55 gallons of a 60%acid solution in order to get an 80% acid solution?

Question

Mathematics

Leonidas Barrett

4 December, 08:28

How much pure acid should be mixed with 55 gallons of a 60%acid solution in order to get an 80% acid solution?

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Answers (1)

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Tootsie · Answer 1

Work in amount of pure acid let x = gallons of pure acid required.

then we have the equation:-

x + 55 (0.6) = 0.80 (x + 55)

x + 33 = 0.80x + 44

0.20x = 11

x = 11/0.2 = 55 gallons answer