3x-2y=13 2x+3y=-16 are these lines parallell or perpendicular or neither

3x - 2y = 13

-2y = - 3x + 13

y = 3/2x - 13/2 ... slope is 3/2, y int is - 13/2

2x + 3y = - 16

3y = - 2x - 16

y = - 2/3x - 16/3 ... slope = - 2/3, y int is - 16/3

perpendicular lines will have negative reciprocal slopes. To find the negative reciprocal of a number, flip the number and change the sign.

On the 1st equation, the slope was 3/2 ... find its negative reciprocal ... flip it, making it 2/3 ... change the sign ... making it - 2/3. So the negative reciprocal of 3/2 is - 2/3.

So if one equation has a slope of 3/2 and another equation has a slope of - 2/3, then these lines are perpendicular <==