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16 September, 04:15

Part of a cheerleading routine is throwing a flyer straight up and catching her on the way down. The flyer begins this move with her center of gravity 4 feet above the ground. She is thrown with an initial vertical velocity of 30 feet per second.

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  1. 16 September, 06:39
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    What is the rest of the question?
  2. 16 September, 08:02
    0
    The formula would be

    y=4 + 30t - 16t^2

    Her maximum height is when the velocity is zero. so V = 30 - 32t 0 = 30 - 32t t=15/16 seconds.
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