Ask Question
20 May, 13:19

1. Derive the quadratic formula from the standard form (ax2 + bx + c = 0) of a quadratic equation by following the steps below.

2. Divide all terms in the equation by a.

3. Subtract the constant (the term without an x) from both sides.

4. Add a constant (in terms of a and b) that will complete the square.

5. Take the square root of both sides of the equation.

6. Solve for x.

+4
Answers (1)
  1. 20 May, 16:50
    0
    We are given that:

    a x^2 + b x + c = 0

    Divide all terms with c / a:

    x^2 + (b / a) x + (c / a) = 0

    Subtract c from both sides:

    x^2 + (b / a) x + (c / a) - c / a = 0 - c / a

    x^2 + (b / a) x = - c / a

    Add a constant k to complete the square:

    where k = ((b / a) / 2) ^2 = (b / 2a) ^2

    x^2 + (b / a) x + k = - c / a + k

    x^2 + (b / a) x + (b/2a) ^2 = - c / a + (b / 2a) ^2

    So the perfect square trinomial is:

    (x + b/2a) ^2 = - c / a + (b / 2a) ^2

    Taking the square root of both sides:

    x + b/2a = sqrt [ - c / a + (b / 2a) ^2]

    x = sqrt [ (-c/a) + (b / 2a) ^2] - (b/2a)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “1. Derive the quadratic formula from the standard form (ax2 + bx + c = 0) of a quadratic equation by following the steps below. 2. Divide ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers