Ask Question
5 October, 13:20

Year (X) = 2000 2001 2002 2003 2004

Cost in Dollars (Y) = 56.25 74.30 122.75 200.00 308.50

The table shows the cost of a game from 2000 to 2004, which has been increasing in a quadratic fashion. Let x = 0 in 2000, and find the best-fit quadratic equation. What will game cost in 2010?

A) $417

B) $746

C) $960

D) $1,586

+3
Answers (1)
  1. 5 October, 14:22
    0
    Here we are going to use the equation y=15x2+3x+56.

    x=0 in 2,000 so x=10 in 2010.

    Substitute 10 for x.

    After this we have the answer: D. $1,586
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Year (X) = 2000 2001 2002 2003 2004 Cost in Dollars (Y) = 56.25 74.30 122.75 200.00 308.50 The table shows the cost of a game from 2000 to ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers