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19 August, 07:36

How do you find zeros when given a quadratic relation in vertex form

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  1. 19 August, 10:08
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    In order to find the zeros in a quadratic in vertex form, you need to follow a number of steps. They have been outlined for you along with a sample problem.

    y = (x - 2) ^2 - 16

    After getting the original form, you can place a 0 in for y. In is where the graph will cross the x-axis, so it is where you will find both of your zeros.

    0 = (x - 2) ^2 - 16

    Now take the constant and add it to both sides. In this equation, - 16 is your constant. So, we'll add 16 to both sides to begin to solve.

    16 = (x - 2) ^2

    Now we can take the square root of both sides. After we do so, we take both the positive and negative version of what we get. This is because both 4 and - 4 squared is equal to 16.

    +/-4 = x - 2

    Now we add 2 to both sides to get us what is left of x.

    2 + / - 4 = x

    Now that we have a final form such as this, we can separate and get two answers for our two zeros.

    2 + 4 = 6

    2 - 4 = - 2
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