A bucket contains 50 lottery balls numbered 1-50. one is drawn at random. Find p (multiple of 6/2-digit number)

This is a problem of conditional probability that can be calculated by the formula:

P (B | A) = P (A ∩ B) / P (A)

We know that:

- between 1 and 50 there are 41 two-digit numbers, therefore

P (A) = 41/50 = 0.82

- between 1 and 50 there are 8 multiples of six, therefore

P (B) = 8/50 = 0.16

- between 1 and 50 there are 7 two-digits mutiples of six, therefore

P (A ∩ B) = 7/50 = 0.14

Now, we can calculate:

P (B | A) = P (A ∩ B) / P (A)

= 0.14 / 0.82

= 0.17

Therefore, the probability of getting a multiple of 6 if we draw a two-digit number is 17%.