Find the factors and zeros of 6x2 + 8x - 28 = 2x2 + 4?

A) 2 (x + 4) (x + 2); {-4, - 2}

B) 4 (x + 4) (x - 2); {-4, 2}

C) 4 (x - 4) (x + 2); {4, - 2}

D) 4 (x - 4) (x - 2); {4, 2}

First solve the equation:

6x^2 + 8x - 28 = 2x^2 + 4

=> 6x^2 - 2x^2 + 8x - 28 - 4 = 0

=> 4x^2 + 8x - 32 = 0

Extract common factor 4:

=> 4[x^2 + 2x - 8] = 0

Now factor the polynomial:

4 (x + 4) (x - 2) = 0

=> the solutions are x + 4 = 0 = > x = - 4, and x - 2 = 0 = > x = 2.

So the answer is the option B: 4 (x + 4) (x - 2); {-4, 2}