The length of a rectangle is 5 inches more then the width. the area of the rectangle is equal to 2 inches more than 4 times the perimeter. Find the length and width of the rectangle

P = 2 (L + W)

L = W + 5

A = 4P + 2

P = 2 (W + 5 + W)

P = 2 (2W + 5)

P = 4W + 10

A = 4P + 2

A = 4 (4W + 10) + 2

A = 16W + 42

A = L * W

A = W (W + 5)

A = W^2 + 5W

W^2 + 5W = 16W + 42

W^2 + 5W - 16W - 42 = 0

W^2 - 11W - 42 = 0

(W + 3) (W - 14) = 0

W - 14 = 0

W = 14 <==

L = W + 5

L = 14 + 5

L = 19 <==

P = 2 (19 + 14)

P = 2 (33)

P = 66

A = L * W

A = 19 * 14

A = 266

answer : length = 19, width = 14 ... perimeter = 66 ... area = 266