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10 October, 22:30

Find a6 of the geometric sequence: a1=4 and a3=36

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  1. 10 October, 23:37
    0
    Geometric sequence

    an=a1 (r) ^ (n-1)

    so

    given

    a1=4

    and a3=36

    36=a3=4 (r) ^ (3-1)

    36=4 (r) ^2

    9=r^2

    3=r

    an=4 (3) ^ (n-1)

    a6 is

    a6=4 (3) ^ (6-1)

    a6=4 (3) ^5

    a6=4 (243)

    a6=972

    a6=972
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