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15 July, 13:51

One number is six times as large as another. The sum of their reciprocal is 7. What are the numbers

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  1. 15 July, 15:53
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    X=6y

    sum of their reciprocals

    (1/x) + (1/y) = 7

    x=6y

    1/6y+1/y=7

    1/6y+6/6y=7

    7/6y=7

    times both sides by 6y

    7=42y

    divide both sides by 42

    1/6=y

    x=6y

    x=6 (1/6)

    x=6/6

    x=1

    the numbers are 1 and 1/6
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