Solve: 2|x - 3| - 4 ≥ 10

2 (|x-3|) - 4≥10

Step 1: Add 4 to both sides. 2 (| x-3 |) - 4 + 4 ≥ 10+4 2 (| x-3 |) ≥14 Step 2: Divide both sides by 2. 2 (| x-3 |) 2 ≥ 142 | x-3 | ≥7 Step 3: Solve Absolute Value. | x-3 | ≥7 We know either x-3 ≥7 or x-3 ≤ - 7 x-3 ≥7 (Possibility 1) x-3 + 3 ≥ 7+3 (Add 3 to both sides) x≥10 x-3 ≤ - 7 (Possibility 2) x-3 + 3 ≤ - 7 + 3 (Add 3 to both sides) x≤ - 4

the answer is

x≥ 10 or x ≤-4

Hi TeddyBR

Add 4 to both sides

add 10 + 4 to 14

divide both sides by 2

divide 14/2 to 7

break down the problems into these two equations

x - 3 ≥ 7

- (x - 3) ≥ 7

Lets first solve the first equation which is x - 3 ≥ 7 and that would be x ≥ 10 and lets solve the other one which is - (x - 3) ≥ 7 and that would be x ≤ - 4

Gather both solutions

Answers: x ≥ 10 and x ≤ - 4.