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23 May, 13:55

A teacher has two students, one two times as old as the other. The teacher is five times as old as the older student, and in 5 years she will be five times as old as her younger student. Find the teacher's present age.

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  1. 23 May, 14:38
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    Let x = the older student

    Let y = the younger student

    Let z = the teacher.

    x = 2y

    z = 5x

    z + 5 = 5y Somehow this does not look like its going to be nice.

    z = 5y - 5

    Since z = 5y - 5 we have

    5y - 5 = 5x

    y - 1 = x Here's the problem. there is a contradiction. You need to make y bigger, not smaller.
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