In triangle ABC, a = 18.2, ∠B = 62°, and ∠C = 48°. Find b

To find angle a we do 180 - (62+48) = 180-110=70

angle a = 70

with this we can use the sin rule

a/sin (A) = b/sin (B) = c/sin (C)

since we have side a and angle A and angle b we can do:

18.2/sin (70) = b/sin (62)

then we can times by sin (62)

(18.2/sin (70)) * sin (62) = 17.1