Find the 39th term of the arithmetic sequence that starts with 4 and has a common difference of 6.

A. 232

B. 226

C. 238

D. None of these

Any arithmetic sequence can be expressed as:

a (n) = a+d (n-1), a=initial term, d=common difference, n=term number.

We are told that a=4 and d=6 so we have:

a (n) = 4+6 (n-1), so the 39th term is:

a (39) = 4+6 (38)

a (39) = 4+228

a (39) = 232