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26 April, 00:33

What is the equation of a line passing through (-2,2) with a slope of 4/3

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  1. 26 April, 03:07
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    Y = mx + b

    slope (m) = 4/3

    (-2,2) ... x = - 2 and y = 2

    now sub and find b, the y int

    2 = 4/3 (-2) + b

    2 = - 8/3 + b

    2 + 8/3 = b

    6/3 + 8/3 = b

    14/3 = b

    ur equation is : y = 4/3x + 14/3 ... or 4x - 3y = - 14
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