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31 March, 13:10

A rectangular deck has an area of 320ft^2. the length of the deck is 4 feet longer than the width. find the dimensions of the deck. solve by completing the square.

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  1. 31 March, 16:48
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    A = L * W

    A = 320

    L = W + 4

    320 = W (W + 4)

    320 = W^2 + 4W

    W^2 + 4W = 320

    W^2 + 4W + 4 = 320 + 4

    (W + 2) ^2 = 324

    W + 2 = (+-) sqrt 324

    W = - 2 (+-) 18

    W = - 2 + 18 = 16 ft < = = this is the width

    W = - 2 - 18 = - 20 ... not this one because it is negative

    L = W + 4

    L = 16 + 4

    L = 20 ft < = = = this is the length

    in summary ... the width is 16 ft and the length is 20 ft
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