This is a priority! The equation of a parabola is 1/16 (y+3) ^=x+4 what are the coordinates of the focus?

To solve this problem you must apply the proccedure shown below:

1. You have the following equation of a parabola:

1/16 (y+3) ^2=x+4

2. Rewriting the equation of the parabola, you have:

(y+3) ^2=16 (x+4)

3. The vertex of the parabola is:

(h, k) = (-4,-3)

3. Now, you must find the coefficient of the unsquared part, as below:

4p=16

p=16/4

p=4

4. As you can see, the y part is squared and p is positive. This means that the parabola that opens to the right.

5. The focus of the parabola has to be 4 units to the right of the vertex. Therefore, the focus is:

(0,-3)

The answer is: (0,-3)