According to a government commission, 70% of all the nation's households have vcrs. in a random sample of 15 households, what is the probability that have at least 13 vcrs? round to four decimal places.

Number of trials, n = 15

Expected success, r = 13

Probability of having a VCR, p = 70% = 0.7

Probability of not having a VCR, q = 1 - p = 0.3

According to the binomial distribution, the probability of 13 out of 15 households having a VCR is

₁₅C₁₃ p¹³ q¹⁵⁻¹³

= [15! / (13!2!) ] * (0.7¹³) * (0.3²)

= 0.0916

Answer: 0.0916 (or 9.16%)