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15 August, 16:50

Find all values of x such that sin 2x = sin x and 0 ≤ x ≤ 2π.

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  1. 15 August, 16:58
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    Hello:

    sin 2x = sin x and 0 ≤ x ≤ 2π.

    all solutions:

    2x = x + 2k π or x = π - x + 2kπ ... k in : Z

    x = 2kπ or : x = π/2 + kπ

    but:

    0 ≤ x ≤ 2π

    all values of x such that sin 2x = sin x and 0 ≤ x ≤ 2π are:

    k = 0 : x=0, x = π/2

    k=1 : x=2 π, x=3π/2
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