What are the x-intercepts of

y=2x^2-3x-2

Find the x-intercepts by setting the function equal to 0

0 = 2x^2 - 3x - 2

Factor

2x^2 - 4x + x - 2 = 0

2x (x - 2) + 1 (x - 2) = 0

(x - 2) (2x + 1) = 0

x - 2 = 0

x = 2

2x + 1 = 0

2x = - 1

x = - 1/2

the x-intercepts are at x = - 1/2 & 2