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15 February, 20:09

What are the x-intercepts of

y=2x^2-3x-2

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Answers (1)
  1. 15 February, 20:23
    0
    Find the x-intercepts by setting the function equal to 0

    0 = 2x^2 - 3x - 2

    Factor

    2x^2 - 4x + x - 2 = 0

    2x (x - 2) + 1 (x - 2) = 0

    (x - 2) (2x + 1) = 0

    x - 2 = 0

    x = 2

    2x + 1 = 0

    2x = - 1

    x = - 1/2

    the x-intercepts are at x = - 1/2 & 2
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