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7 January, 02:39

A box contains 12 transistors, 3 of which are defective. If 3 are selected at random, find the probability?

All are Defective =

None are defective=

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Answers (1)
  1. 7 January, 05:03
    0
    P (all are defective) = (3/12) ^3 = (1/4) ^3 = 1/64

    P (none are defective) = (9/12) ^3 = (3/4) ^3 = 27/64
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