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27 January, 02:18

Solve the given equation. (enter your answers as a comma-separated list. let k be any integer. round terms to three decimal places where appropriate. if there is no solution, enter no solution.) 5 sin 2θ - 7 sin θ = 0

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  1. 27 January, 02:34
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    5 sin 2θ - 7 sin θ = 0

    we know sin 2θ = 2sinθcosθ

    5 (2sinθcosθ) - 7sinθ = 0

    sinθ (10cosθ - 7) = 0

    sinθ = 0

    θ = 2k*pi, pi + 2k*pi

    cosθ = 0.7

    θ = cos^-1 (0.7) = 2k*pi + cos^-1 (0.7)

    θ = 2k*pi + cos^-1 (0.7)

    θ = 2k*pi - cos^-1 (0.7)
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