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14 August, 08:35

Rewrite this function in the form that reveals the minimum of the function.

c (p) = p^2-28p+250

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  1. 14 August, 10:02
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    Given that the function is given by:

    c (p) = p^2-28p+250

    The minimum value of the function is at the derivative of c' (p)

    thus from the function given:

    c (p) = p^2-28p+250

    c' (p) = 2p-28

    Thus the minimum function is c' (p) = 2p-28
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