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14 September, 19:45

The value of (a-1) + a^2-b^2/1-ab+2 (a-b) / 2b when a=2 and b=-1 is?

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  1. 14 September, 21:12
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    The value of (a-1) + a^2-b^2/1-ab+2 (a-b) / 2b when a=2 and b=-1 will be evaluated as follows:

    substituting the values in the expression we obtain:

    (2-1) + 2^2 - (-1) ^2/1 - (2 * (-1)) + 2 (2 - (-1)) / (2 (-1))

    simplifying the above we get:

    1+4-1/1 - (-2) + 2 (2+1) / (-2)

    =1+4-1+2 (3) / (-2)

    =1+4-1-3

    =5-4

    =1

    Answer: 1
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