Ask Question
16 June, 17:31

Find three numbers in the ratio 2:3:5, the sum of whose squares is 608.

+3
Answers (1)
  1. 16 June, 20:23
    0
    Let the three numbers a, b, c, be 2x, 3x, 5x.

    we know that

    (2x) ^2 + (3x) ^2 + (5x) ^2 = 608

    4x^2 + 9x^2 + 25x^2 = 608

    38x^2 = 608

    x^2 = 608/38

    x^2=16

    x = √16

    x = 4

    a = 2x = 2*4=8

    b=3x = 3*4=12

    c = 5x = 5*4=20

    the three numbers are 8,12,20
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Find three numbers in the ratio 2:3:5, the sum of whose squares is 608. ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers