Approximate the zeros of the function. Round to the nearest tenth if necessary. f (x) = 4x^2 + 4x - 35. Explain each step on how you got there.

4x²+4x-35=0

factor: (2x+7) (2x-5) = 0

2x+7=0, or 2x-5=0

2x=-7 or 2x=5

x=-3.5 or x=2.5

I don't see any rounding necessary in this case.

when you factor ax²+bx+c, you take the two factors of a and the two factors of c, one factor of a times one factor of c, the other factor of a times the other factors, the sum of the two products make b.

in this case, the factors of 4 is 2 and 2, the factors of - 35 is - 5 and 7. I line them up in the following way:

2 - 5

2 7

then I multiple them diagonally, the top left 2 multiplying the bottom right 7=14, and the other 2 multiplying - 5=-10, 14 and - 10 make a sum of 4.

if you don't get the desired sum, switch the factors up and down till you have the right combination. Note: Do not switch left and right.

I hope this makes sense to you.