Ask Question
6 April, 20:26

A cylinder's radius is reduced to two-fifths its original size and the height is quadrupled. How has the volume of the cylinder changed?

+3
Answers (1)
  1. 6 April, 23:31
    0
    Let the original volume be pi * r^2 * h where r = radius and h = height.

    The new volume will be pi * (2/5 r) ^2 * 4h = pi*4/25 r^2 4h

    pi*4/25r^2 * 4h / pi r^2 h = 4/25 * 4 = 16/25

    The volume has been reduced by factor of 16/25.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A cylinder's radius is reduced to two-fifths its original size and the height is quadrupled. How has the volume of the cylinder changed? ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers