The perimeter of a rectangle is 38 ft. The length is 9 ft longer than the width. Find the demensions. Write a system of linear equations and solve the resulting system. Let x be length and y be width.

Question

Mathematics

Sammy Ryan

25 July, 12:38

The perimeter of a rectangle is 38 ft. The length is 9 ft longer than the width. Find the demensions. Write a system of linear equations and solve the resulting system. Let x be length and y be width.

+5

Answers (1)

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Darnell Orozco · Answer 1

P=38

P=2x+2y=2 (x+y)

x=9+y

so

38=P=2 (x+y)

38=2 (x+y)

divide both sides by 2

19=x+y

x=9+y

19=9+y+y

19=9+2y

minus 9 both sides

10=2y

divide by 2

5=y

sub back

x=9+y

x=9+5

x=14

x=14

y=5