What is the probability that three standard die, all rolled at the same time, will all land with a three facing up?

Okay lets change the question a bit that won't matter b'coz the question will be same after all. Instead of finding probability that 3 dices will land with a 3 facing up, find the probability that the 3 dices will land with same no facing up.

S=sample space

n (S) = number of total outcome of sample space=6*6*6=216 {since there are 3 dices}

E=events that all 3 dices land with a same no facing up

n (E) = no of ways in which the dice will have same no=6

{b'coz at a time,; one face with same no will be facing up and in a dice there is 6 faces ... so at 6 different favourable ocassion there are 6 ways that the dice will have same no}

then probability of getting same no is,

P (E) = n (E) / n (S)

=6/216 = 1/36 ANS ...