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24 May, 17:20

Find the zeros of the function. f (x) = 9x^3 + 36x^2 + 27x

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Answers (2)
  1. 24 May, 19:58
    0
    9x^3 + 36x^2 + 27x=0

    9x (x^2 + 4x + 3) = 0

    9x (x+3) (x+1) = 0

    9x=0; x=0

    x+3=0; x=-3

    x+1=0; x=-1

    answer

    x=0; x=-1; x=-3
  2. 24 May, 21:00
    0
    We can take out x so x = 0 is one of the zeroes.

    In fact the GCF is 9x so:-

    9x (x^2 + 4x + 3) = 0

    x^2 + 4x + 3 = 0

    (x + 3) (x + 1) = 0

    giving x = - 1 or - 3

    The three zeroes are 0, - 1 and - 3.
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