Form a sequence that has two arithmetic means between 13 and 88. a. 13, 38, 63, 88 c. 13, 25, 25, 88 b. 13, 88, 163, 238 d. 13, 50.5, 88

Form a sequence that has two arithmetic means between 13 and 88. a. 13, 38, 63, 88

The formula to use for this problem is this: an = a1 + (n - 1) d

Where:

a1 = 13

a4 = 88

n = 4

d = ?

Thus, we have:

88 = 13 + (4 - 1) d

88 - 13 = 3 * d

75 = 3d

75/3 = d = 25

Therefore, d = 25.

This means that, a difference of 25 exist between successive number in the sequence. So the right sequence is 13, 38, 63, 88.

The correct option is A.