G={ (-9,6), (-6,4), (2,-6), (6,-5) }

h (x) = 3x-4

find the following

g^-1 (-6) =

h^-1 (x) =

(h^-1·h) (3) =

A) The ordered pair with - 6 as the dependent value is (2, - 6).

g^-1 (-6) = 2

b) Swap x and y and solve for y.

x = 3y - 4

x + 4 = 3y

(x + 4) / 3 = y

Then the inverse function can be written as

h^-1 (x) = (x + 4) / 3

c) You have shown the product of h^-1 (x) and h (x). We have to assume that is what you intend.

h^-1 (3) = (3 + 4) / 3 = 7/3

h (3) = 3*3 - 4 = 5

(h^-1·h) (3) = h^-1 (3) ·h (3) = (7/3) ·5

(h^-1·h) (3) = 35/3

If you intend (h^-1◦h) (3), that value is 3.