If the least common multiple of 2 numbers is 60 and one number is 7 less then the other number what is the answer

Your question is not clear. I must guess what you meant. Did you mean "Find the two numbers?"

If so, let the two numbers be m and n. Then mn=60 and m=n-7.

Then (n-7) (n) = 60, or n^2 - 7n - 60 = 0. This factors: (n+5) (n-12) = 0

Thus, n = - 5 or n = 12.

check: does mn = 60? Does 12*5 = 60? Yes. Is m (which is 5) 7 less than n (which is 12) ? Yes.

Note that you could also check to see whether n=-5 and m=n-7=-5-7=-12 is also a solution.