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6 April, 10:20

Three books (x, y, and z) rest on a table. x is on table, while y is stacked upon x, and z is stacked upon y. the weights of the books are mx = 4 n, my = 10 n and mz = 5 n. the net force acting on book y is:

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  1. 6 April, 13:16
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    Refer to the diagram shown below.

    The free body diagram of book y indicates:

    a weight of 5 N from book z, and a reaction of 5 N on book z;

    a weight of 10 N acting on book x, and a reaction of 10 N from book x

    The net downward force on book y is

    5 + 10 - 10 = 5 n.

    Answer: 5 N, downward.
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