How can 1/4x - 3 = 1/2x + 8 be set up as a system of equations?

Answers (2)
  1. Alanis
    Equation (1) y=1/4x-3

    Equation (2) y=1/2x+8
  2. Leonie
    For this case, the first thing you should do is define the following variables:

    y = 1 / 4x - 3

    y = 1 / 2x + 8

    We now rewrite the equations:

    4y = x - 12

    2y = x + 16

    We place the variables on the left side of the equality:

    4y-x = - 12

    2y-x = + 16

    From where we obtain the system of equations sought.

    Answer:

    The system of equations is:

    4y-x = - 12

    2y-x = + 16
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