What are the zeros of the function

y = (x+3) (x+2) (x-2) ?

If you are asking about the x-intercepts, then

x=-3, x=-2, and x=2; this is because these numbers make the equation equal to 0 (or make y=0)

(3,0), (-2,0), and (2,0)

If you are asking about the y-intercept, then you make x=0, which makes the equation (3) times (2) times (-2) which equals - 12.

So, the y-intercept is - 12.

(0,-12)