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31 May, 10:59

Twice the sum of a number and 7 is equal to 3

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  1. 31 May, 11:49
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    Let n = the number.

    Twice the sum of a number and 7 = 3 would be 2 (n+7) = 3. Divide by 2 on both sides to get n+7 = 3/2. Then subtract 7 from both sides to isolate the variable n.

    n = 3/2 - 7. N = - 5.5 or - 11/2
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