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20 June, 12:34

Solve for x: log5 (3*-1) = 2

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  1. 20 June, 14:30
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    If 5 is the base, 3 (x-1) is the argument:

    3x-1=5²

    3x=26

    x=26/3

    If 5 is with 3x-1, that is, if 5 (3x-1) is the argument, and the base is 10:

    5 (3x-1) = 10²

    3x-1=20

    3x=21

    x=7
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