What is the center of the circle given by the equation (x-2) ^2 + (y+4) ^2 = 6

The equation of circle with center (g, f) and radius r is given by,

(x-g) ² + (y-f) ² = r²

Now, compare equation (x-2) ² + (y+4) ² = 6 with the above equation.

g = 2 and f = - 4

Therefore, center of the circle is (2,-4)