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16 December, 21:41

Y=1/8x+c is the family of solutions of the differential equation y'=-8y^2, find the solution that satisfies the initial condition y (0) = 3

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  1. 16 December, 22:20
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    Y (0) = 3 (1/8) ·0 + c = 3 c = 3 y = (1/8) ·x + 3;
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