The sum of the digits of a two-digit number is 8. When the digits are reversed, the number increases by 36. Find the original number.

You can represent a two digit number with vars x, y as x*10+y

I:x+y=8

II:reversed=original+36:

y*10+x=36+10*x+y=

=y*9=36+9*x

=y=4+x

insert y into formula I:

=x+y=8

x + (4+x) = 8

2x+4=8

2x=4

x=2

So the original number is x*10+y=26

x=2 y=6

I: 2+6=8

II: 6*10+2=2*10+6+36=

=60+2=26+36=62