Find 3 consecutive positive integers such that the product of the first and third integers is 48. Solve algebraically.

Question

Mathematics

Turner Curry

Today, 09:46

Find 3 consecutive positive integers such that the product of the first and third integers is 48. Solve algebraically.

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Answers (1)

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Sheba · Answer 1

Let integers be x, x+1 and x+2

x (x + 2) = 48

x^2 + 2x - 48 = 0

(x + 8) (x - 6) = 0

x = 6 (because the integrs are positive

so the 3 numbers are 6,7 and 8.