There are 4 consecutive integers that have a sum of 58. what is the least of these integers?

Easy way

58:4 = 14.5 is center of the integers

13 is the least of these integers

14

15

16

Equations:

4 consecutive numbers

X, X+1, X+2, X+3

13, 14, ... 15 ... 16

X + X+1 + X+2 + X+3 = 58

4X + 6 = 58

4X = 58-6 = 52

X = 52/4 = 13