Costs for standard veterinary services at a local animal hospital follow a normal distribution with a mean of $88 and a standard deviation of $24. what is the probability that one bill for veterinary services costs between $42 and $133?

Question

Mathematics

Jaylen Matthews

23 January, 18:05

Costs for standard veterinary services at a local animal hospital follow a normal distribution with a mean of $88 and a standard deviation of $24. what is the probability that one bill for veterinary services costs between $42 and $133?

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Answers (1)

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Joshua Mack · Answer 1

the probability that one bill for veterinary services costs between $42 and $133 will be given as follows

P (42
z = (x-μ) / σ

where:

μ-mean

σ-standard deviation

thus

when x=42:

z = (42-88) / 24=-1.92

thus

P (x<42) = 0.0281

when x=133

x = (133-88) / 24=1.875

thus

P (x<133) = 0.9699

Thus

P (42
=0.9699-0.0281

=0.9418

Answer: 0.9418