A rectangle shape whose length is 4 inches less than twice its width. the area is 30 square inches. whats the dimension

Using the given information, we can say the following:

Width (W) = x

Length (L) = (2x - 4)

Area of Rectangle = L * W

Using this, we can formulate an equation for rectangle in question:

x (2x - 4) = 30

Expand and move everything to one side:

2x² - 4x - 30 = 0

Simplify by dividing everything on both sides by 2:

x² - 2x - 15 = 0

Factorise:

(x + 5) (x - 3) = 0

Set each factor equal to 0 and solve for x:

x + 5 = 0

x = - 5 (a dimension cannot be negative so this is not the solution we want)

x - 3 = 0

x = 3 (this is the solution)

x = W = 3"

L = 2x - 4

L = 2 (3) - 4

L = 2"

So, the length the rectangle is 2" and the width is 3"