Use matlab to calculate the probability to get 3 times of '5' in 8 throws of a fair die

P = 1/6, the probability of getting a '5' in a throw of the dice.

q = 1 - p = 5/6, the probability of not getting a '5'.

Number of trials = 8

Expected number of successes = 3

The probability is

₈C₃ (1/6) ³ (5/6) ⁵ = 56*0.00463*0.40188 = 0.1042

Answer: 0.1042