Ask Question
22 August, 20:16

A regular octagon has side length 10.9 in. The perimeter of the octagon is 87.2 in and the area is 392.4 in2. A second octagon has side lengths equal to 16.35 in. Find the area of the second octagon. A. 461.60 in2 B. 882.9 in2 C. 717.06 in2 D. 642.66 in2

+3
Answers (1)
  1. 22 August, 20:52
    0
    Both regular octagons are similar, so we can apply the concept of similar shape regarding the length of the side and the area.

    If the scale factor of side is 'n' then the scale factor of the area is 'n²'

    Octagon A's side length = 10.9

    Octagon B's side length = 16.35

    Scale factor of side length = 16.35 : 10.9 = 1.5

    Scale factor of area = 1.5² = 2.25

    Area of octagon A = 392.4

    Area of octagon B = 392.4 * 2.25 = 882.9 in²

    Correct answer: B
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A regular octagon has side length 10.9 in. The perimeter of the octagon is 87.2 in and the area is 392.4 in2. A second octagon has side ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers