Suppose that you have 8 cards. 5 are green and 3 are yellow. the 5 green cards are numbered 1, 2, 3, 4, and 5. the 3 yellow cards are numbered 1, 2, and 3. the cards are well shuffled. suppose that you randomly draw two cards, one at a time, and with replacement. â¢ g1 = first card is green â¢ g2 = second card is green enter the probability as a fraction. p (g1 and g2)

Question

Mathematics

Natalee

14 December, 22:40

Suppose that you have 8 cards. 5 are green and 3 are yellow. the 5 green cards are numbered 1, 2, 3, 4, and 5. the 3 yellow cards are numbered 1, 2, and 3. the cards are well shuffled. suppose that you randomly draw two cards, one at a time, and with replacement. â¢ g1 = first card is green â¢ g2 = second card is green enter the probability as a fraction. p (g1 and g2)

+5

Answers (1)

Know the Answer?

Khalil Larsen · Answer 1

25/64 Since the draws are with replacement, the events are independent. So the probability of drawing a green card is 5/8 since there's 5 green cards out of a total of 8 cards. And since they events are independent, simply multiply the probability of each event together. 5/8 * 5/8 = 25/64